Ukrainian tennis player Sergiy Stakhovsky won the first round at Wimbledon on July 2, defeating Portuguese João Sousa.
Stakhovsky, 32, triumphed over Sousa with a score of 6-3, 6-3, 5-7, 1-6, 6-4. The match lasted three hours and 29 minutes.
Stakhovsky ranks 109th in the Association of Tennis Professionals.
Stakhovsky started the first set confidently, winning his serves. He made a break in the sixth game, leading 4-2. The first set ended at 6-3 in the Ukrainian’s favor.
In the second set, players continued to serve well. Having no chance for a break, the two were on the way to a tie-break, but in the seventh game, Stakhovsky made one more break point. The second set ended at 6-3 in Stakhovsky’s favor.
In the third set, Sousa made an early break point, leading 1-3. In this set the players started to make mistakes, losing three serves in a row. Sousa won the last three games, winning the third set with a score of 5-7.
The worst set for the Ukrainian was the fourth one. Stakhovsky won his serve and then lost six games in a row. Sousa confidently won the fourth set with a score of 1-6. An early break by the Ukrainian allowed him to lead in the fifth set with a score of 3-1. Stakhovsky won all his serves, winning 6-4 in the final set.
Stakhovsky will next play at Wimbledon on July 4 against Sam Querrey of the U.S.
